t^2-10t+10=0

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Solution for t^2-10t+10=0 equation:


Simplifying
t2 + -10t + 10 = 0

Reorder the terms:
10 + -10t + t2 = 0

Solving
10 + -10t + t2 = 0

Solving for variable 't'.

Begin completing the square.

Move the constant term to the right:

Add '-10' to each side of the equation.
10 + -10t + -10 + t2 = 0 + -10

Reorder the terms:
10 + -10 + -10t + t2 = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -10t + t2 = 0 + -10
-10t + t2 = 0 + -10

Combine like terms: 0 + -10 = -10
-10t + t2 = -10

The t term is -10t.  Take half its coefficient (-5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
-10t + 25 + t2 = -10 + 25

Reorder the terms:
25 + -10t + t2 = -10 + 25

Combine like terms: -10 + 25 = 15
25 + -10t + t2 = 15

Factor a perfect square on the left side:
(t + -5)(t + -5) = 15

Calculate the square root of the right side: 3.872983346

Break this problem into two subproblems by setting 
(t + -5) equal to 3.872983346 and -3.872983346.

Subproblem 1

t + -5 = 3.872983346 Simplifying t + -5 = 3.872983346 Reorder the terms: -5 + t = 3.872983346 Solving -5 + t = 3.872983346 Solving for variable 't'. Move all terms containing t to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + t = 3.872983346 + 5 Combine like terms: -5 + 5 = 0 0 + t = 3.872983346 + 5 t = 3.872983346 + 5 Combine like terms: 3.872983346 + 5 = 8.872983346 t = 8.872983346 Simplifying t = 8.872983346

Subproblem 2

t + -5 = -3.872983346 Simplifying t + -5 = -3.872983346 Reorder the terms: -5 + t = -3.872983346 Solving -5 + t = -3.872983346 Solving for variable 't'. Move all terms containing t to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + t = -3.872983346 + 5 Combine like terms: -5 + 5 = 0 0 + t = -3.872983346 + 5 t = -3.872983346 + 5 Combine like terms: -3.872983346 + 5 = 1.127016654 t = 1.127016654 Simplifying t = 1.127016654

Solution

The solution to the problem is based on the solutions from the subproblems. t = {8.872983346, 1.127016654}

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